Driver Circuit

I was seeing some circuits for a Cockroft-Walton multiplier.Most of them seem to be using an AC input voltage.My specific query is ,would this multiplier work with a uni-polar (pulsed DC) input. For example a square wave from 0~100V for example. TIA

  • \$\begingroup\$ An interesting application of this idea: DEC R-series logic (as used in the original PDP-8) uses the change between its -3v and 0v logic levels along with a single stage multiplier to generate a +3v signal that is used to activate edge-triggered latches, producing a much simpler equivalent to the standard D-type flip flop we use in most sequential logic circuits today. See description here. \$\endgroup\$
    – Jules
    Nov 19, 2018 at 3:10

1 Answer 1


It should work perfectly, just be sure that the first capacitor can discharge when the output is 0, a push pull configuration can be useful for your application

Edit: added a schematic for you


simulate this circuit – Schematic created using CircuitLab

Also sorry it looks this way, but circuit lab doesn't allow for diagonal components

  • \$\begingroup\$ Thanks for replying,but could not quite grasp that.Any link or a diagram,if your time permits ? \$\endgroup\$
    – EmbSysDev
    Nov 18, 2018 at 11:39
  • 1
    \$\begingroup\$ You first! Show us where your pulsed DC is coming from. \$\endgroup\$
    – Dave Tweed
    Nov 18, 2018 at 13:20
  • \$\begingroup\$ Yes,I should have shown the circuit before. I have attached an image file,hope it is view-able. \$\endgroup\$
    – EmbSysDev
    Nov 19, 2018 at 17:52
  • \$\begingroup\$ the schematic you show should work proerly \$\endgroup\$
    – diegogmx
    Nov 20, 2018 at 2:55

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