1
\$\begingroup\$

I need a band pass filter that only accepts frequencies from 1000 to 1400 Hz and then toggles the transistor. It has to work from .1 Vpp to 1 Vpp and rejects anything else. I have been testing this circuit in different ways and I keep getting a similar result.

In the circuit my source is .0005 Vpp I have changed it to .05 Vpp and only the dB value changed.

This is the circuit and its simulation This is another variation with a 2 Vpp input and 12V DC input into the opamps

\$\endgroup\$
  • 1
    \$\begingroup\$ Hi hevansa98 and welcome to SE.EE. There is major flaws in your shematic. Firstly, why are the supplies for the op amp only 1mV? That doesn't make any sense. \$\endgroup\$ – Linkyyy Nov 18 '18 at 20:31
  • \$\begingroup\$ The project parameters are from 1mV to 1V \$\endgroup\$ – hevansa98 Nov 18 '18 at 20:37
  • 1
    \$\begingroup\$ Check with your prof -- 1mV as an op-amp supply makes no sense, but 1mV to 1V for the incoming signal does. \$\endgroup\$ – TimWescott Nov 18 '18 at 20:47
  • \$\begingroup\$ He does this to test LTSpice the parameters are correct (as weird as they may be), but what else could be wrong? \$\endgroup\$ – hevansa98 Nov 18 '18 at 20:54
  • \$\begingroup\$ @hevansa98: Im pretty sure you are supposed to vary the input V1, and not the power supples V2 and V3 \$\endgroup\$ – Linkyyy Nov 18 '18 at 20:57
1
\$\begingroup\$

A single analog filter that accepts 0.1 Vpp at 1000 Hz, but rejects 1.0 V at 999 Hz would be extremely challenging to design. More so if it needed to work with real world components (that are not all exactly at their nominal values, drift over temperature, etc).

Consider breaking up the problem into two parts.

One circuit measures the signal frequency. Another circuit measures the signal amplitude.

Only if both circuits detect a "good" result is the output enabled.

A useful circuit to measure the frequency could be a frequency-to-voltage converter, available as an IC from various vendors, although you could also roll your own using established techniques.

A useful circuit to compare the output of this circuit with established limits is a window comparator.

You can use google to find numerous designs for either of these circuits.

Realistically, you will need to allow some tolerance in your specs. Accepting a 1000.000 Hz signal and rejecting a 999.999 Hz signal is not even theoretically possible if you don't allow your circuit at least on the order of 1000 s to make the frequency measurement, and the techniques that can do it use complex digital circuits, not analog ones.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.