I have an old flashlight that says "15W Police Waterproof" on the handle, the battery compartment is normally for 3 type C batteries, unfortunately the bottom battery leaked and is stuck in there. Would it be possible to power this up from a 5V USB powerbank?
I don't want to burn the LED, is the driver more voltage-tolerant than the LED and will accept the higher voltage?
What has got my attention mostly is the note "AAA*3/AAA*4". - does it mean it can operate between 4.5-6 Volts?
PS: If you were going through the circuit, it might be helpful to know that the flashlight has 3 modes that cycle with power button - bright-dimm-strobe.
PS2: The whole powerbank (image below) fits in the compartment.
Note: I don't trust the 15W label as I have not found a single 15W LED on the internet.
Click an image for high-res.
Search tags: HT-4.5S/1 , B17332A
So I have tried to power it:
- The cheap powerbank immediately shuts down (and needs a reset by connecting a charger) as the output is too high. Such a shame. I guess I can't have nice things.
- It draws 5.06V @ 0.23A (1.2W) at low mode
- It draws 5.26V @ 1.94A (10.2W) at high (my source is limited to 2A per port)
I will try it with a Y cable.
- See compared High mode with 5W source and 10W source:
Also included is the back side of PCB, the power switch is inserted between the central piece and positive source. Negative source is connected to the casing.
The flashlight is indeed around 10 years old.