I believe the purpose of this circuit is to perform SQ decoding. It is supposed to shift the phase 90 from 100Hz to 10Khz. I'm interested in listening to the quad version of the Pink Floyd Animals LP, and, I came across a bigger circuit, on a 70's electronics magazine, of which this network is a part of. So, my goal is to make this circuit, but I would also like to understand the phase shifting network.
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\$\begingroup\$ Where is it supposed to produce the shifted phase? I assume across R4, but you haven't mentioned it. Also, PLEASE redo your drawing to put V1 to the left of V2, so we don't have to guess whether or not the ground connection includes V2 and C3. \$\endgroup\$– WhatRoughBeastNov 29, 2018 at 23:02
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\$\begingroup\$ Also, that's not going to work as given. With V2 at 20 V RMS, that will be about 56 Vpk-pk. Running that into a 25 volt amp will severely clip the signal, and I don't like to think what that will do to the subsequent RC networks. \$\endgroup\$– WhatRoughBeastNov 29, 2018 at 23:06
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\$\begingroup\$ Sorry, I got the print before the last changing ion the circuit. This is the final version. \$\endgroup\$– Gabriel SantosNov 29, 2018 at 23:11
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\$\begingroup\$ First off, I'm new to this forum, so, sorry for my mistakes, and I don't know how to post another picture. \$\endgroup\$– Gabriel SantosNov 29, 2018 at 23:13
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1\$\begingroup\$ Easiest way to skin this these days is just to rip the thing into your PC, then use a hilbert transform to get the phase shift. Real analogue phase shift networks do exist but a reasonably stable 90 degrees over 3 decades of bandwidth is a big network of strange valued precision caps and resistors. Look in the ham radio literature for design examples from 'phasing' SSB sets for the basic method. \$\endgroup\$– Dan MillsNov 30, 2018 at 0:04
1 Answer
The circuit works as follows: @WhatRoughBeast is correct, the voltage must be low enough so that everything stays under the power supply voltage. The input is level shifted with C3, R7, and R8 so that it is basically the same signal at the base except that it is centered about midway between V1 and ground. Q1 emitter is basically a voltage follower one diode drop below this midpoint. So the signal at Q1 is pretty much the same amplitude and phase as the input. Because the gain (beta) of the transistor is high, we can say that the collector and emitter current is almost identical, so that the voltage on the collector is the same amplitude as the voltage on the emitter, but is 180 degrees out of phase. So you have two voltage sources, one in phase and one out of phase, and they are connected to your load through different impedances. You can do the math but intuitively you can see that as the frequencies change, the contributions from the two voltage sources also change so that the phase shift does not change as much with frequency as it would with a simple RC. It does not provide a true constant phase shift. If you want a constant 90-degree phase shift, you can do a much better job with a simple op amp circuit. However, musician types looking for new sounds often experiment until they get what they want, especially in the era you mentioned when op amps were not available.
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\$\begingroup\$ The very simple circuit will have barely any separation between the 4 channels. 42 years ago I made an SQ Full Logic circuit using Motorola MC1312 decoder, MC1314 voltage controlled attenuator and MC1315 logic ICs. Records recorded with SQ play with good channels separation and ordinary stereo plays with interesting channels levels changes. \$\endgroup\$ Jul 18, 2021 at 18:08