Hi guys i have two problems.

1.Where to connect the transmitter coil to the oscillator part?

2.How to make the output of the oscillator stronger? because someone told me that the output coming from the oscillator is weak. i need a stronger output to make a decent magnetic field from the coils.

im just new to electronics and i want to learn more, hope you can help me guys enter image description here

| improve this question | | | | |
  • \$\begingroup\$ Have you gotten the oscillator and receiver working yet? \$\endgroup\$ – Marla Dec 1 '18 at 13:21
  • \$\begingroup\$ yes sir..my oscillator runs at 1 Mhz \$\endgroup\$ – dumbedkid Dec 1 '18 at 13:26
  • 1
    \$\begingroup\$ I actually think you "kind of" have the answer at your hand. Only you didn't put all the puzzle piezes together. Can I ask you three questions? 1. what needs to happen to the transmitter coil for it fulfill its purpose? 2. Why did you add a "Coupling capacitor" to your transmitter coil (you didn't do that randomly!)? 3. Why is there C4 on the Colpitts oscillator? (hint: one of C4, C7 is redundant.) \$\endgroup\$ – Marcus Müller Dec 1 '18 at 14:16
  • \$\begingroup\$ oh and hint: the first thing you'd attach to your receiver (watch the order of "ei" in "receiver"!) is not an Arduino, but a multimeter, or if you you have, an oscilloscope, in parallel to a resistor. \$\endgroup\$ – Marcus Müller Dec 1 '18 at 14:18
  • \$\begingroup\$ im sorry i forgot to remove the other capacitor...my main problem is where to connect the transmitter coil pins to the oscillator..can you pls edit the schematic. \$\endgroup\$ – dumbedkid Dec 1 '18 at 14:34

Connecting the coil to the oscillator is easy.

The coil goes from the point marked "Output" to the ground of the transmitter circuit.

Getting more power is trickier.

Your circuit uses the 2N2222 transistor both as an oscillator and to provide power to the coil.

Rather than messing with a circuit you've found on Youtube, I would recommend starting over with a better circuit. Pretty much any circuit has to be better.

The existing circuit doesn't let you vary the frequency of the transmitter. You need to do this to hit the resonant frequency of the inductor/capacitor (LC) resonant circuit formed around the coil and its companion capacitor. If your oscillator isn't running at the resonance frequency, then you will lose a lot of power in the transfer. The oscillator might be built so as to oscillate at the tank frequency, but given that you are asking how to attach the coil I expect you have taken an oscillator circuit from somewhere and are trying to use it to drive your (not matching) coil.

You could add an amplifier to the existing circuit, but that's just throwing more power into it without making things really better - you will still be throwing away a lot of power.

For this to work, you need three things:

  1. Transmit and receive tank circuits with the same resonance frequency. You appear to have coils with the same inductance but you seem to have different capicitors to go with them. The receiver and the transmitter will therefore have different resonance frequencies.

  2. An oscillator that runs at the resonance frequency of the tanks. Your oscillator runs at some frequency which may or may not be close to the resonance frequency of the tanks. It has no simple way to change the frequency, even if you knew what frequency is needed.

  3. Power. The 2N2222 is a small signal transistor. It doesn't want to deal with the current it would take to transfer large amount of power. It will burn out before you get significant amounts of power through the coil.

I suggest starting over with a circuit for a system in which all of that has been considered.

This question on this site goes into detail of a very simple system

Resonance of the tanks is covered.

The oscillator is built such that it naturally oscillates at the resonant frequency of the tanks.

It uses a much beefier transistor that will allow more transmit power.

Then there's this site which appears to be someone's homework or class assignment.

It goes into some detail about the theory, and provides a system that works.

It uses a separate oscillator that you tune to the resonance frequency of the tanks, and an amplifier to provide more power to the transmit coil.

Either of those would work better than what you've got.

I recommend reading the text in both links. It is all good information about how wireless power works.

| improve this answer | | | | |
  • \$\begingroup\$ i have read the the links sir..but im still lost..why did they used square wave instead of sine wave? i thought you need a sine wave to produce a magnetic field on the coils and..btw i forgot to change the value of the capacitor on the transmitter part when editing the schematic the capacitor should be the same with the capacitor on the receiver side \$\endgroup\$ – dumbedkid Dec 2 '18 at 3:03
  • \$\begingroup\$ The 555 produces square waves - that's what it is made to do. The square wave is also easier on the transistor - it is either fully on or fully off. That way there's almost no power wasted in the transistor - it doesn't get hot. The coil doesn't care (much) what waveform you drive it with. It is resonant at only one frequency - that one goes through both coils as a proper sine wave. \$\endgroup\$ – JRE Dec 2 '18 at 9:18
  • \$\begingroup\$ oh i see, i thought square wave is the same with DC so i ask why they use square wave instead of sine wave.. i have read also that you cant create a magnetic field on a coil if you use a DC \$\endgroup\$ – dumbedkid Dec 2 '18 at 10:06
  • \$\begingroup\$ You can create a magnetic field around a coil with DC. That's how electromagnets work. \$\endgroup\$ – JRE Dec 2 '18 at 11:01
  • \$\begingroup\$ so basically theres no difference using sine or square wave? \$\endgroup\$ – dumbedkid Dec 2 '18 at 11:12

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.