0
\$\begingroup\$

With a simple filter circuit (either high pass or low pass), I'm seeing unexpected behavior in the o-scope output when I use a resistor with a low ohm value (e.g., 10 Ohms). Since a picture is worth 1000 words, here's my o-scope readout at the cutoff frequency (with a waveform generator creating sin waves at 160 KHz, w/amplitude of 11 V): Picture of o-scope

Here's the high pass filter circuit design I'm using:

enter image description here

There are probably several issues, but from my POV at least two issues appear relative to other circuits I've built and tested: 1) The dual sin waves offset by half a cycle, one faint and one 'blurry'. Note: the 'faint' wave flickers rapidly and is not always there. 2) The amplitude is a fraction of what I would expect (and what it is with other circuits I build w/higher ohm resistors). In this case I was expecting a voltage of ~8 V.

If I try other higher ohm resistors, they seem to work fine and I get readouts that have Bode plots in-line with expectations (e.g., 22k Ohm, 500pF for a cutoff of 14 KHz has a clean readout with a drop in signal that matches expectations).

Question: Why does this behavior occur when using a low ohm resistor, while higher ohm ones work fine?

Any help or reference links that will help me understand would be greatly appreciated. Apologies if I missed something basic, new to hobby electronics.

\$\endgroup\$
3
  • \$\begingroup\$ What is your capacitor value? \$\endgroup\$ Dec 4, 2018 at 6:57
  • \$\begingroup\$ 500pF is the capacitor, and resistor is 10 ohm. \$\endgroup\$
    – Thomas
    Dec 4, 2018 at 7:00
  • 1
    \$\begingroup\$ The flickering wave is probably due to triggering on noise spikes, which appears to be significant in your picture. \$\endgroup\$
    – Sven B
    Dec 4, 2018 at 8:07

1 Answer 1

4
\$\begingroup\$

Treat the capacitor as a frequency dependent resistor and you end up with a voltage divider. With low resistance to the GND side your signal will be near 0V.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.