I'm looking to wire up an off-grid system. What I'm stuck on is battery placement.

The likelihood is my batteries will need to be quite far apart (almost 2 metres). My question is how does this relate to the wire thickness I should use to add components to the circuit?

To flesh this out in case I'm not being clear: if I only use one battery, the fusebox can be 50cm away from both positive and negative terminal. Using a certain wire thickness, this could result in an X% voltage drop since the return distance of the current is 1m.

If I use the batteries in parallel, the positive terminal is now 50cm from the fusebox, whilst the negative terminal (on the other battery) is now 1.5m away. Does this means the return distance is now 2m, resulting in a 2X% voltage drop? Or does it include the parallel connections, meaning it's 3.5m or 5m?

Any help greatly appreciated!


Yes, basically you have it right, more distance means greater voltage drop.

So, best thing to do is locate the batteries safely with proper venting, then consider your cable run.

To limit the voltage drop, which is due to the resistance of the cable ie proportional to length and inversely proportional to diameter, all you need to do is put in a nice thick cable which will compensate for the length.

So, if the maximum current from the batteries is 20A, then the cable is relatively cheap. If the current will be about 100A, then you are looking at the size of cable used for car battery to starter motor - which as it has more copper is more expensive.

Good cables and decent connections are cheaper than a fire...

  • \$\begingroup\$ Thanks Mike! As I'm looking at 300A discharge currents, I'm already looking at some of the thickest cable you can buy. My question really is how the parallel batteries work into the equation so I can size them right. Is it the total cable length (from positive, to device, to negative, AND the cable length connecting the two batteries), or are the parallel connections only considered in themselves since they're essentially supplying the other battery, or am I way off in understanding how this works? \$\endgroup\$ – J. Carter Dec 7 '18 at 9:50
  • \$\begingroup\$ As the batteries are in parallel, you could size the cables so that the cable current carrying capacity is matched to the position that the cable is used, BTW never seen that done... So, all the cable links are normally sized for the maximum current to flow, so that the possibility of error is removed. \$\endgroup\$ – Solar Mike Dec 7 '18 at 9:56

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