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I want to express the current function based on the next graph

enter image description here

So using the slope and the coordinates in the third interval the current will be \$i(t)=\begin{cases} 0\,A & 0\,s<t<t_{1}\,s\\ 7\,A & t_{1}\\ y-7=\frac{8-7}{t_{2}-t{1}}(x-t_{1}) A& t_{1}<t<t_{2}\\ 8\,A & t_{2}\\ \\ \end{cases}\$

This is the right approach? I intend to use the expression to calculate the average and rms current. Also if can point me more problems like this.

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    \$\begingroup\$ masteringelectronicsdesign.com/… \$\endgroup\$ – Sunnyskyguy EE75 Dec 24 '18 at 1:24
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    \$\begingroup\$ Yes, it's the right approach. \$\endgroup\$ – joe electro Dec 24 '18 at 3:09
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    \$\begingroup\$ What's ‘x’, what’s ‘t2’, what’s ‘y’? Also, what happens at t>t2? \$\endgroup\$ – Chu Dec 24 '18 at 10:53

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