I want to express the current function based on the next graph

enter image description here

So using the slope and the coordinates in the third interval the current will be \$i(t)=\begin{cases} 0\,A & 0\,s<t<t_{1}\,s\\ 7\,A & t_{1}\\ y-7=\frac{8-7}{t_{2}-t{1}}(x-t_{1}) A& t_{1}<t<t_{2}\\ 8\,A & t_{2}\\ \\ \end{cases}\$

This is the right approach? I intend to use the expression to calculate the average and rms current. Also if can point me more problems like this.

  • 1
    \$\begingroup\$ masteringelectronicsdesign.com/… \$\endgroup\$ – Sunnyskyguy EE75 Dec 24 '18 at 1:24
  • 1
    \$\begingroup\$ Yes, it's the right approach. \$\endgroup\$ – joe electro Dec 24 '18 at 3:09
  • 1
    \$\begingroup\$ What's ‘x’, what’s ‘t2’, what’s ‘y’? Also, what happens at t>t2? \$\endgroup\$ – Chu Dec 24 '18 at 10:53

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Browse other questions tagged or ask your own question.