0
\$\begingroup\$

The circuit is;

schematic

simulate this circuit – Schematic created using CircuitLab

For given 2 port network, Im shorting V1 to solve for y22 and y12 and apply a current source at V2.[Y-Parameters]

This is the circuit we get;

schematic

simulate this circuit

Now my question is; what will be io (current through 3-ohm resistor branch) will be equal to? Will it flow through 6-ohm resistor ? Or will it be equal to "zero"?

\$\endgroup\$
  • \$\begingroup\$ If you include R1 in your circuit diagram, in parallel with the short-circuit, what's the current through it? \$\endgroup\$ – Chu Dec 27 '18 at 14:05
  • \$\begingroup\$ @Chu I believe the current will flow into least resistive path, in other words will ignore 3-Ohm resistor. \$\endgroup\$ – calculusnoob Dec 27 '18 at 14:07
  • \$\begingroup\$ That's correct. \$\endgroup\$ – Chu Dec 27 '18 at 14:09
  • \$\begingroup\$ @Chu So you are implying "io" will be equal to zero ? since "io" is the current through 3-ohm resistor. \$\endgroup\$ – calculusnoob Dec 27 '18 at 14:10
  • \$\begingroup\$ Yes............ \$\endgroup\$ – Chu Dec 27 '18 at 14:12

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Browse other questions tagged or ask your own question.