The circuit is;


simulate this circuit – Schematic created using CircuitLab

For given 2 port network, Im shorting V1 to solve for y22 and y12 and apply a current source at V2.[Y-Parameters]

This is the circuit we get;


simulate this circuit

Now my question is; what will be io (current through 3-ohm resistor branch) will be equal to? Will it flow through 6-ohm resistor ? Or will it be equal to "zero"?

  • \$\begingroup\$ If you include R1 in your circuit diagram, in parallel with the short-circuit, what's the current through it? \$\endgroup\$ – Chu Dec 27 '18 at 14:05
  • \$\begingroup\$ @Chu I believe the current will flow into least resistive path, in other words will ignore 3-Ohm resistor. \$\endgroup\$ – calculusnoob Dec 27 '18 at 14:07
  • \$\begingroup\$ That's correct. \$\endgroup\$ – Chu Dec 27 '18 at 14:09
  • \$\begingroup\$ @Chu So you are implying "io" will be equal to zero ? since "io" is the current through 3-ohm resistor. \$\endgroup\$ – calculusnoob Dec 27 '18 at 14:10
  • \$\begingroup\$ Yes............ \$\endgroup\$ – Chu Dec 27 '18 at 14:12

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