I was trying to solve this unbalanced Wheatstone bridge and found that the current $i$ in the mid wire is 9A .This result was achieved by using node voltage method.
Then I rearranged the same circuit to the form shown in the second image.
and at this point I flipped the right half of the circuit so as to obtain the equal resistors on the same side.
now I again rearranged the circuit as shown.
Here, the final circuit is a balanced Wheatstone bridge and thus the current i must be 0.
So clearly something went wrong in there.
I saw a post a quesiton before this one just to make sure that there is no mistake in rearranging the circuit in the way I have done.
It was answered by the user PhillipWood as being correct and was unfortunately put on hold.
So can someone please point out what exactly went wrong with the above method.