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I have built an inverter circuit, where the circuit works properly for light AC loads e.g. 9 watts, 230V LED bulb etc. and gives an output voltage of 200v, but if I use a 70 watts, 230V exhaust fan as my load, it doesn't work and voltage across the load is found to be 30V. What is the problem and what should I do, to make it work properly for any load?

I have attached my schematic diagram:

enter image description here

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closed as unclear what you're asking by winny, Bimpelrekkie, pipe, laptop2d, RoyC Jan 9 at 13:55

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

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    \$\begingroup\$ I have attached my circuit diagram No you haven't, that's not a circuit diagram. Circuit diagrams use proper symbols for components and look like: i.stack.imgur.com/NUxu0.png Your drawing just shows how to connect the components, it gives no information about the functionality of those components. A proper circuit diagram does show that. \$\endgroup\$ – Bimpelrekkie Jan 8 at 8:26
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    \$\begingroup\$ What's the rated output of this circuit? What do you expect if you connect for example a 2 kW load? \$\endgroup\$ – pipe Jan 8 at 8:30
  • \$\begingroup\$ Rated output voltage is 200V at light AC load and using heavy loads like AC Motor, the Voltage ouput is around 30v, why? If I connect any load it should work properly without any voltage drop, what should l do? \$\endgroup\$ – al rizwan khan mehboob ali Jan 8 at 10:03
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    \$\begingroup\$ No inverter works at any load. You seem to have copied this from somewhere, so you need to find documentation about it. \$\endgroup\$ – pipe Jan 8 at 10:17
  • \$\begingroup\$ "Rated" means "how much it was designed for." You have told us what it really produces, not what it was designed to produce. \$\endgroup\$ – JRE Jan 8 at 12:00
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https://www.youtube.com/watch?v=5QaKiXRa-n0

https://www.youtube.com/watch?v=zASxHFxf6oY

These two videos, especially the first one, answers this issue, and I believe the first video uses exactly the same circuit as the one you posted.

TLDW: Your circuit does not have closed loop control (basically, a way for the circuit to sense the output voltage and adjust the operation to meet the desired output voltage), and also because that transformer likely can't push enough power through it to power a big load like a fan, it goes into saturation which means most of its power is wasted as heat inside the transformer core, and not into the secondary (where your load is connected)

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