-1
\$\begingroup\$

I was wondering if there are any good IC's available for doing this. I have been thinking up some ways to do it, however, I am sure there are most efficient methods. I am not too well versed with all the different types of integrated circuits and their differences, so I was hoping to get some guidance on this. I plan to use 4 AA batteries with a 5V buck/boost voltage regulator to get a steady 5V rail. I need, however, both 5V and -19V to -21V for the device I am making. Would anyone be able to help me with how to generate the negative rail?

My main constraints are size and cost, however, I would love it to be as efficient as possible to prolong battery life.

Thanks

New contributor
Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.
\$\endgroup\$

closed as off-topic by Elliot Alderson, Dave Tweed Jan 11 at 18:40

This question appears to be off-topic. The users who voted to close gave this specific reason:

If this question can be reworded to fit the rules in the help center, please edit the question.

  • \$\begingroup\$ please update your question with all of the information ..... the required current is unknown \$\endgroup\$ – jsotola Jan 11 at 18:35
  • \$\begingroup\$ Your specification is incomplete, which makes this unanswerable. How much current do you need? How accurate must the voltage be? How much ripple can you tolerate? \$\endgroup\$ – Dave Tweed Jan 11 at 18:35
  • \$\begingroup\$ As written, this question reads like a shopping question ("what should I buy"), which is off-topic here. It doesn't have to be, though; you should be able to modify the question into something on topic that will get good answers. \$\endgroup\$ – Hearth Jan 11 at 18:36
  • \$\begingroup\$ Most of the major chip vendors (most notably, TI's Webench, but there are others) have web-based tools that help you with part selection and even circuit design. You just need to enter all of your design parameters. \$\endgroup\$ – Dave Tweed Jan 11 at 18:40