I am searching for a solution to charge a battery pack (7S1P)[ICR18650] with a charger with CC/CV mode and I have a BMS for protection (I've done research to maximise the security of the battery pack).

I wanted to know if the CC mode of the charger will cause issues with the dc/dc converter.

The batteries may power equipment while charging.

I want to allow the use of the batteries only when the charger is not plugged in.

Here is the schematic enter image description here

And the BMS I will be using in this project: enter image description here

  • \$\begingroup\$ You'll need to clarify quite a lot. What exactly are the batteries connected directly to? Is the charger on the output of the regulator? What's the input rating of the charger? What about part numbers? What's this board you're talking about? \$\endgroup\$ – Hearth Jan 13 '19 at 20:32
  • \$\begingroup\$ Can you just draw a schematic? \$\endgroup\$ – Hearth Jan 13 '19 at 20:34
  • \$\begingroup\$ I've added the schematic and more informations \$\endgroup\$ – loyo1000 Jan 13 '19 at 20:57
  • \$\begingroup\$ What is the power taken by the dc-dc converter \$\endgroup\$ – Anil CS Nov 30 '19 at 20:10

Your DC/DC converter will be safe as long as the battery is in-circuit, but you may mess up your battery charging. If your BMS open-circuits the connection to the battery your system as a whole probably won't work, but as it's malfunctioning the charger will probably hold its output to what it thinks a battery pack should have.

That converter will put a load on the battery pack. In general, the load won't mess up the gross behavior of the charger, but it will mess up charge tracking and termination. This is because the charger will not be able to properly account for how much charge is actually going into the battery

The CC mode of charger is there for one of two reasons: to hold the current going into the battery to protect the battery, or to hold the power level of the charger down to protect the charger. You decide how much you want to spend on the charger and you choose. Any current going into your load is going to be stolen from the battery; if it isn't measured at the battery, the charger will not be able to properly track the amount of charge going into the battery.

The most basic way of implementing charge termination on a Li-whatever pack is to monitor the current in CV mode, and terminate charge when the current has dropped below some threshold. Again, with your load, the charger will see the combined battery + load current as just the battery current, and it will never terminate charging.

I don't know your system constraints, but I think your best bet is to look for a charger/BMS combination that's designed to handle exactly this situation (there's chips out there to do it in smaller systems; there have to be modules out there, too).

  • \$\begingroup\$ It's not exactly and voltage regulator, it's an DC/DC converter I need it to have an stabilized 24V for the motherboard. I will not build the charger, i will buy it. The CC part is for the initial charging process of the battery, and the charger will cut-off the charging process at 4.2v like the bms (one or the other first). I just want to know if the DC/DC converter will "burn" if I put it like that in the schematic? And have your advise to build it the "good way" \$\endgroup\$ – loyo1000 Jan 13 '19 at 21:05
  • \$\begingroup\$ I modified my answer re. the DC/DC converter. I already said how to do the battery charging the "good" way -- get a charger that "understands" that the battery may be supplying a load at the same time it's being charged, and that can accept a battery current measurement for the purposes of charge management. Either that, or see if the BMS will determine charge completion for you, and see if you can monitor that and turn off charging appropriately. \$\endgroup\$ – TimWescott Jan 14 '19 at 1:19

My biggest concern with this setup is the load detection in the charger might be confused with an extra load in parallel with the battery. LIon chargers typically run a constant current then constant voltage to charge, and an extra load (that is variable current) might cause the charger to mistake which party of the charging curve it is on.

If you keep the DC to DC off while charging then the above circuit will work. Otherwise you may want to find a better setup.


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