I'm just a bit confused about this current transducer/sensor https://uk.rs-online.com/web/p/current-transducers/1383472/

Datasheet: https://docs-emea.rs-online.com/webdocs/15c5/0900766b815c5532.pdf

I can't seem to figure out the reason for the reference voltage. Is the output voltage = to -2V when -250A is being pushed and = to +2V when +250A is being pushed? And is it linearly scaled? I.e would +1V mean +125A?

How exactly is the output working here?


1 Answer 1


The reference voltage is what the transducer produces on its output when measuring 0A.
So if 250A measured gives +2V out, then what you'll actually see at the output is 4.5V (2.5 + 2).
Similarly, for -250A you'll see 0.5V (2.5 - 2).

It appears that you can also drive the reference voltage to a value of your choosing, so you can set the output voltage for 0A to whatever level is convenient for your application.

Yes, the scaling is linear (at least within the limits of error shown in the datasheet).


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.