0
\$\begingroup\$

Suppose that a lithium-ion cell having total charge capacity Q=10Ah is discharged at a rate of 1A for 30min. What is the net change in the cell's state of charge (in percent)? Round to the nearest percent.

\$\endgroup\$
  • 7
    \$\begingroup\$ Reads too much ltke a homework question to deserve an answer. What have you done so far and where are you stuck? \$\endgroup\$ – Brian Drummond Jan 26 at 11:53
  • \$\begingroup\$ on coursera queston is there.but now i got answer. i was little confuse with signs while solving. \$\endgroup\$ – Mrunal Girame Jan 28 at 5:57
1
\$\begingroup\$

$$\Delta Q = I \Delta T$$ right? You're given

$$ I = 1A \\ \Delta T = 0.5 h \\ \Delta Q = I \Delta T = 0.5 Ah \\ Q_0 = 10 Ah $$

Thus $$Q_0 - \Delta Q = 9.5 Ah$$ You subtract because of implications of the word "discharge". Alternatively you could say that the current I is negative.

\$\endgroup\$
  • \$\begingroup\$ yup its -10% . i got it later \$\endgroup\$ – Mrunal Girame Jan 28 at 5:59

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.