You have, I suspect, not really understood CAN systems. The important part is that all communication is conducted on a buss - that is, a single twisted pair which runs from one end of the system to the other. All devices connected to the buss do so as stubs which should be as short as possible (0.1 meter is the standard max, and shorter is better). No branches are allowed. In general, the impedance of commercially available twisted pair is about 120 ohms.
For proper operation, each physical end of the buss should have a terminating resistor of (nominally) 120 ohms. These two resistors are what you have included in your schematic.
The two resistors on your schematic will not appear on a single pcb. For each device, there will be one or zero, depending on where the device sits on the buss.
Another approach is not to include the terminating resistors on the device cards at all, but to install them at each end of the buss, then install transceivers where appropriate.
TLDR; The schematic is wrong. Make the board with room for one resistor. If you have only two units on the buss, install a resistor on each. If you have more than two on the buss, install the resistor only on the two boards at each end of the twisted pair (and make sure the wires do not extend past the board). Do not install the resistor on the intermediate units.