# How to reduce inrush current for DC Motor in boom barrier gate application?

I'm using 24V 25W 100RPM DC geared motor for boom barrier gate application.So I added an overload protection for that circuit but whenever the motor starts the inrush current is produced and it triggers the overload protection circuit.How will I reduce the inrush current? Some say about soft-start but that doesn't fit for my application.

• You may need that inrush current to overcome the mechanical inertia... – Solar Mike Jan 30 at 5:25

24V 25W 100RPM DC geared motor That is about 1 amp of current but does not include startup current or 'jammed motor' current. Startup is at least 3 to 5 amps for a 10th of a second. A 1 ohm 10 watt wirewound resistor can choke back the high start current, as the voltage drop across the resistor is 1 volt per amp of current the motor draws, but this simple trick is limited to a 2 ohm resistor at 20 watts.
NOTE: it triggers the overload protection circuit. There is the assumption that the power supply has enough current to start and run this motor. If the power supply is not rated for 3 to 5 amps at 24 volts then a more robust power supply maybe the answer, still possibly using the resistor.