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First let me say that I understand that this question is best answered by someone familiar with relevant standards (whatever those may be).

Let me give some background. When I'm designing a board at work I usually separate my circuits into several classes. Two of those classes are "signals" and "AC". Nets in the signals class are, e.g., 3.3 or 5 VDC level and may be present on things like user interfaces (the end user doesn't come into direct contact with these nets, but will come closer than to nets in any other class). The AC class contains line voltage nets like 120 or 240 VAC.

For safety we set design rules that say there must be, e.g., 0.250" between nets in the signals class and nets in the AC class. Let's pretend that this clearance is called for by some standard that we would like our products to meet (I don't know if that is true). The nets in the signals class are isolated from nets in AC class by some kind of transformer that can withstand a few kV.

Usually I include the protective earth net in the class AC. This means that signals nets can't come within 0.250" of board mounting points that will be connected to PE.

Now my question. Is this kind of isolation clearance usually required between protective earth and these low level nets? Protective earth is, by definition, accessible to the end user and is considered safe so I see no reason that I would require this large physical isolation distance.

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  • \$\begingroup\$ UL 61010-1 has a table on page 55 that says a possible option between a hazardous part and a accessible parts is basic insulation and protective bonding (protective earth). That does not require a specific large clearance between protective earth and low voltage stuff. \$\endgroup\$
    – uglyoldbob
    Commented Jan 30, 2019 at 18:46
  • \$\begingroup\$ I don't see why you would need to maintain any separation between protective earth and low voltage circuitry. However, there are a lot of requirements surrounding how protective earth is implemented. You WOULD need to insure your product satisfies these requirements because they are intended to prevent protective earth from ever becoming energized at dangerous voltages. Generally, all externally accessible conductive surfaces must be connected together with low-Ohm connections. Hopefully you get an authoritative answer from someone. \$\endgroup\$
    – user57037
    Commented Jan 30, 2019 at 20:01
  • \$\begingroup\$ @uglyoldbob Thanks for that, that's the kind of answer I'm looking for. \$\endgroup\$
    – cholz
    Commented Jan 30, 2019 at 20:13
  • \$\begingroup\$ @mkeith Thanks. I understand what you're saying. Here I am assuming PE meets all safety requirements. \$\endgroup\$
    – cholz
    Commented Jan 30, 2019 at 20:13
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    \$\begingroup\$ @ThreePhaseEel It would be class I in this case. \$\endgroup\$
    – cholz
    Commented Jan 31, 2019 at 0:42

1 Answer 1

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Some I/Os carry a chassis reference by design, so you can't isolate PE from user signals in the general case

Some types of signal connectors (most notably, audio connectors) carry a chassis ground (instead of a signal ground) by design. This is quite important for balanced audio interconnects using TRS or XLR connectors; connecting pin 1 on an XLR or sleeve on a TRS connector to signal ground in an audio application leads to what one calls a "Pin 1 Problem", where noise from the cable shield is injected into the signal reference and thus into the device as a whole.

As a result, it is not possible to maintain a general clearance rule between chassis earth/IO reference earth, which is connected to protective earth given that we are talking about a Class I appliance here, and signals, as your I/O protection and filtering devices will need to be referenced to I/O reference earth as well.

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  • \$\begingroup\$ In my case the signals are completely isolated from chassis earth, but still I think your answer tells me that this kind of isolation is not necessary for safety. \$\endgroup\$
    – cholz
    Commented Jan 31, 2019 at 1:14

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