Intuitively I get it that my SSB power has to be half of DSB power but mathematically I am unable to get this. Say working for tone modulation.

$$m(t)=mA\cos(w_mt)$$ where m is modulation index.

Modulated signal for DSB case is $$mA\cos(w_mt)\cos(w_ct)$$ Power is $$(ma)^2/4$$.

Modulated signal for SSB case is $$mA\cos((w_m-w_c)t))$$ Power is $$(ma)^2/2$$.

This seems total opposite to what appears intuitively . I used BP Lathi's Book on Communication where the formula for SSB is ssb signal=$$m(t)cos(w_ct)+m_h(t)sin(w_ct)$$ where $$m_h(t)$$ is the Hilbert transform on m(t).


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.