I'm using a buck converter(OKR-T/10-W12-C made by Murata Power Solutions). The converter supports 4.5 ~ 14.0V input.
The input is 9.5V voltage from the another buck device.
And between of them, the schottky diode SR54L is stationed. So, because of the diode, some voltage drop occurs(0.2 ~ 0.3V) but the input is 9.5V so the voltage drop will not come a big problem.
Then, have to I use a schottky diode? Or, can I remove the diode?
Which way is more efficient to make less power dissipation? I want to use less power because of the efficiency but I'm worried about the heat dissipation of the converter. Will dividing the heat with schottky diode just not good solution for the heat sharing? Will using the diode can affect to the performance of the converter?
(Using heatsink is impossible because the converter is too small to use a heatsink.)