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I want to build balance control for two audio amplifier circuits, and I want to use dual gang pot.

I want to know if I connected it directly to the outputs of the two audio amplifiers circuit then to the speakers if the the resistance go to about 0 ohm will it be ok for 10W output.

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    \$\begingroup\$ Wouldn't you be better off connecting it to the amplifier inputs? \$\endgroup\$ – HandyHowie Feb 8 at 14:03
  • \$\begingroup\$ I don't know I connected volume control to amplifier inputs but I want to know what will happen in this case \$\endgroup\$ – Romyo Feb 8 at 14:05
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    \$\begingroup\$ 125mW = 0.125W... \$\endgroup\$ – rdtsc Feb 8 at 14:06
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    \$\begingroup\$ No, it'll burn out pretty rapidly. \$\endgroup\$ – pjc50 Feb 8 at 14:46
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    \$\begingroup\$ If it drops the power down to 125mW you're kind of defeating the purpose of your amplifier, anyway. \$\endgroup\$ – Hearth Feb 8 at 15:54
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I want to know if I connected it directly to the outputs of the two audio amplifiers circuit then to the speakers if the the resistance go to about 0 ohm will it be OK for 10W output.

No.

  • Potentiometers are usually rated at 0.125 W.
  • The maximum current the pot can handle is given by \$ P = I^2 R \$ which can be rewritten as \$ I = \sqrt {\frac {P}{R}} \$. If you choose, for example, a 100 Ω potentiometer then \$ I = \sqrt {\frac {0.125}{100}} = 35 \ \text {mA}\$.
  • With an 8 Ω loudspeaker this would give you about \$ P = I^2 R = 0.035^2 \times 8 = 0.01 \ \text W \$ from you speaker.

The correct way to reduce speaker volume is to reduce the amplifier input signal level using a potentiometer.

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