I'm trying to design a wide band RF receiver(say 5MHz to 5GHz).

The antenna:

  • How long would the antenna have to be to pick up this range?
  • I read that the antenna width would have to be at least as long as the half wavelength so would I have to use a 30m antenna to receive a 5MHz signal?
  • Would I be able to pick up a 5GHz Signal with that same 30m antenna?
  • And to pick up the signal the circuit would have to have a resonant frequency equal to that of the RF signal?

Are there any good resources out there I should look at?

  • 3
    \$\begingroup\$ You've got way more than one question here. I'd suggest first asking just about the antenna. If you still think this is a viable project after learning more about that, then give us another question about the receiver circuit. \$\endgroup\$ – The Photon Sep 26 '12 at 4:27
  • \$\begingroup\$ half wavelength or λ/4 ??? \$\endgroup\$ – perilbrain Sep 26 '12 at 5:54
  • \$\begingroup\$ The Biconical antenna is often used for EMI detection purposes, but even that would be challenged over a 3 decade range. Do you want to accurately measure field strength or just detect the presence of RF. What field strengths do you expect? Are you limited to a single antenna? \$\endgroup\$ – MikeJ-UK Sep 26 '12 at 9:37

If a very wide range of frequencies needs to be covered usually Log-peridoc antennas are used.

I doubt, however, if you can use one single antenna effectively to cover the range of 5MHz to 5GHz (factor 1000!).

  • \$\begingroup\$ Ok thank you! so it looks like i'll need to use two antennas? \$\endgroup\$ – nwnoga Sep 28 '12 at 23:28
  • \$\begingroup\$ @nwnoga: I guess you need even more than 2. Some Log-periodic antennas can cover a range of factor ca. 10. I.e. in that case you would still need at least 3: 5-50 MHz, 50-500 MHz, 500-5000 MHz. \$\endgroup\$ – Curd Sep 30 '12 at 18:59

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.