# Moving summing block before integrator

I wanted to move the summing operation (+10) that I perform before the integrator block as shown below: (MODEL-1)

I check in this wikibook page - https://en.wikibooks.org/wiki/Control_Systems/Block_Diagrams and from the transformation "Moving a Summing Junction in front of a Block", it says to add a 1/P block, which in this case would be a differentiator. I tried adding a differentiator block like below, but the outputs (taken @ every 100th clock cycle) of the blocks does not match. (MODEL-2)

The output from MODEL-1 is:

The output from MODEL-2 is:

This is one part of this question.

However the major part is, when using this filter practically, the input to this filter contains high-frequency noise(now - just for example, it contains a pure sinusoid). By adding a differentiator in the front for the purpose of transformation dissolve the whole purpose of filtering?

• Where do you want to add this offset? To From3 usually for a single polarity signal source to make it bipolar, you subtract a positive offset to make the input to the discrete transform bipolar. – Sunnyskyguy EE75 Feb 11 at 18:41
• @SunnyskyguyEE75 I want to move this offset(+10) to the beginning of the integrator block. – sundar Feb 11 at 18:47
• I don’t see a single integrator block – Sunnyskyguy EE75 Feb 11 at 18:48
• @SunnyskyguyEE75 $\frac{z}{z - 1}$ is the integration operator in the Z domain. I suppose properly it's called the "accumulation" operator due to being a discrete-time thing, but people call it integration anyway. – Hearth Feb 11 at 18:50
• @Hearth so at DC where offset is applied to the input , is it an integrator? – Sunnyskyguy EE75 Feb 11 at 20:20