Here is the question provided below:
My first question is how is the current 10 A flowing towards the voltage source???? Shouldn't it be in the opposite direction. I feel like my professor is using an opposite convention which is really irritating b/c in all my ECE courses I have been taught to use plus to minus as the current direction for voltage source. Should I just ignore all his currents direction(since I don't know what convention he is using) and relabel all my circuits?
Second question is if I were to do a mesh analysis on 3 loops going in a clock wise direction should the left most loop with the current source just have an equation where current i going around in a clockwise direction just simply set to 5A?
EDIT: and also if 5 Amps are flowing in to the node between R2 and 5 ohm resistor the equation would become
\$I_{in}=I_{out\:}\$ so ... \$5\:=\:8\:+\:i_2\$
\$i_2 = -3\$
which would make \$i_2 = -3\$???????? so in that case i_2 would be flowing upward which makes zero sense to me because by looking at the circuit the 5 amps from the current source should split up at the node between R2 and 5 ohm in both down ward direction.
Edit2: but then again I might be just flat out wrong about everything I said. Please help a fellow engineering student out.
Edit3 I will solve this circuit and post my solution for you (if you choose to help meout) to check it out b/c I am still unsure, if my assumptions are correct or wrong. Thanks for all your input.
FINAL EDIT
\$I_{in\:}=\:I_{out}\$
\$5\:=\:8\:+\:i_2\$
\$i_2 = -3\$
\$I_{in\:}=\:I_{out}\$
- \$8\:=\:10+ i_3\$
- \$i_3 = -2\$
I am going to set a ground at the node right below R1. Then using intuition, i_3 is going actually in the upward direction since \$i_3\$ sign was found to be negative. So \$5*i_3 = 10 \$. So a 10 volt drop from the ground to the node right of the 50 voltage source.
So the node to the right of the 50 Volt voltage source is supposedly at -10 V. Then you go across left and drop 50 Volts. So the node where \$i_2\$ comes in, it should be at -60V which means V_1 should equal to -60 V?
But that value does not make sense if you do KCL at the node where i_2 comes in.
Can someone please verify my answers? I will post my hand worked solution on a paper if necessary.
And what exactly is a "negative resistor" is this something that I was supposed to know b/c this term was never brought up during class. I have a hunch that he mislabeled some current direction b/c this homework is just supposed to be a simple review for basic circuitry.