# Circuit drawing more current on PCB [closed]

I have a circuit that I developed on breadboard. I have then soldered it on a PCB and it is now drawing more current on PCB compared to when it was on breadboard. I only want to discuss possible reasons for this without going into much detail about the circuit as I haven't changed it before or after soldering on PCB unless someone really wants me to.

• Micro-controller based circuit.
• A couple sensors and a single radio.
• Step-up regulator for powering everything (Pololu 5V).

This is what comes to my mind:

• Flux conducting some current?
• Possible tiny short-circuit somewhere?
• Possible faulty chip after soldering?
• Possible different current consumption with different power supplier? (3.6V lipo battery over a cheap AC 1A 5V adapter)
• Possible larger resistance on breadboard circuit.

The circuit works fine so I assume there is no problem with PCB.

Thanks everyone.

## closed as unclear what you're asking by Eugene Sh., Elliot Alderson, Edgar Brown, Leon Heller, brhansFeb 13 at 18:00

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• This is not a discussion forum, sorry. Without specific question there is no specific answer. – Eugene Sh. Feb 13 at 17:23
• This site is structured around having a specific question with a "correct" answer. Without circuit details the question is unanswerable, as there are umpteen possible reasons for the discrepancy, and exhaustively listing these to cover every possible circuit is not reasonable. – Kevin Kruse Feb 13 at 17:26
• You said that the power consumption changed but then you talk about changing current. Which is it? Please explain your manufacturing and assembly process in detail, if you won't describe the circuit. – Elliot Alderson Feb 13 at 17:27
• What do you get for actual power consumption then? What happens if you multiply supply voltage by supply current in both cases? – Elliot Alderson Feb 13 at 17:35
• If you're expecting "an exhaustive answer for possible reasons", then pretty much by definition your question is too broad for this site (and the reason for my close vote), although it looks to me as if JYelton has found your non-issue. – brhans Feb 13 at 18:02

Breadboard: $$\P = 5 \times 0.0285 = 142.5\mathrm{mW}\$$
PCB: $$\P = 3.6 \times 0.04 = 144\mathrm{mW}\$$