I've tried to divide current at 8A and then make a Kirchhoff voltage law between the resistor and dependent current source but I still can't solve it.

enter image description here

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    \$\begingroup\$ you have to show some effort... present what have you done so far \$\endgroup\$ – thece Feb 15 '19 at 16:11
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    \$\begingroup\$ Not only effort in solving the problem, but in presenting the question. I've edited your question with capitalization and punctuation. \$\endgroup\$ – JYelton Feb 15 '19 at 16:18
  • \$\begingroup\$ You should also replace that image with a larger one that is in focus. \$\endgroup\$ – K H Feb 15 '19 at 21:22

i think that after dividing the current of 8A, you can sum up the currents in the second contour enter image description here

  • \$\begingroup\$ but im not really sure \$\endgroup\$ – ervis nilo Feb 15 '19 at 16:23
  • \$\begingroup\$ You can accept your own answer. \$\endgroup\$ – Tyler Feb 15 '19 at 16:25
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    \$\begingroup\$ You've posted this in the "Answer" section. Can you please use this edit link to add this information into your "Question" instead? \$\endgroup\$ – Kevin Kruse Feb 15 '19 at 16:25
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    \$\begingroup\$ @KevinKruse sorry first day still learning lol \$\endgroup\$ – ervis nilo Feb 15 '19 at 16:28
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    \$\begingroup\$ Why does your KCL equation not include terms for current through the 8-ohm resistor or the 4 A source? Hint: Step 1 is to combine the 8 A and 4 A sources. \$\endgroup\$ – The Photon Feb 15 '19 at 16:33

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