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I want to simulate a motor with a resistor and inductor. It means I want to connect a resistor and inductor to 1-phase or 3-phase instead of a motor. For achieving this goal I have to measure both active and reactive power and calculate the value of resistor and inductor. Is it possible? I mean is it a right way to consume active and reactive power with resistor and inductor? And if it is right, how is the connection of resistor and inductor. Parallel or series?

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  • \$\begingroup\$ What about back EMF? \$\endgroup\$
    – mkeith
    Feb 17 '19 at 5:55
  • \$\begingroup\$ I just want to consume active and reactive power \$\endgroup\$
    – Hamed P
    Feb 17 '19 at 6:00
  • \$\begingroup\$ The resistor should consume some power. But it is not clear what your goal is. Maybe experimenting with a simulator would help you accomplish your goals. \$\endgroup\$
    – mkeith
    Feb 17 '19 at 6:04
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    \$\begingroup\$ You can put the components in either series or parallel, and calculate how much actual and reactive power they will consume, in order to test your meter. Then having gained confidence in your meter, you can use it to measure your motor. Is that what you want to do. \$\endgroup\$
    – Neil_UK
    Feb 17 '19 at 6:15
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    \$\begingroup\$ As Neil said I want to test my meter and I wanted to know if it measures the reactive power right or not. And I don't have any motor or other devices that consume reactive power and I thought of using inductor instead of a motor \$\endgroup\$
    – Hamed P
    Feb 17 '19 at 6:23
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Since i can not comment, i will post my comment as an answer. I concluded that you do not have a lot of experience since you posted this: "If I connect a 100uh 10A inductor in series with a 500wat resistor is it possible".

From your initail question i deduced that you want to connect the resistor and inductor to the mains voltage, do not do this without knownig the resulting current. Preferably, do not do this with the mains voltage at all, get a signal generator. Depending on the frequency of the signal you are working with calculate the inductor impendance $$ Z=\omega L $$, and make sure the inductor is in its limits. Next choose a resistor with approximately the same resistance in ohms as the inductor. Connect them is series or parallel and work with that.

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  • \$\begingroup\$ Thanks for your reply. As you said I don't have enough experience in this field. Is it important that the resistor and inductor be in the same value? \$\endgroup\$
    – Hamed P
    Feb 19 '19 at 17:37
  • \$\begingroup\$ The resistance of the resistor should be about the same value as the impendance of the inductor at the given frequency. This assures that the voltage across each of them is about the same when they are connected in series, and your measurements will therefore be more accurate. \$\endgroup\$
    – Ziggy
    Feb 20 '19 at 9:09
  • \$\begingroup\$ Thanks for the useful information. I want to test it with 3-phase and it seems it's a little dangerous! what is your advice for me? \$\endgroup\$
    – Hamed P
    Feb 20 '19 at 9:50
  • \$\begingroup\$ Get an ac power source with current limiting, or use somthing like this: link, just make sure you dimension the components(the resistor and inductor) so that the resulting current the source provides does not exceed its limit, and the current trough the individual components does not exceed the components limit. \$\endgroup\$
    – Ziggy
    Feb 20 '19 at 10:53
  • \$\begingroup\$ Thank you, Ziggy. I will test it and share the results. Can I have your email or something else to get in touch with you? This is my Gmail: hpexeph@gmail.com \$\endgroup\$
    – Hamed P
    Feb 23 '19 at 7:39

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