Copper wire wrapped around an iron core produces current when a strong magnet is moved in its vicinity.
I gather the "magnet movement" part is expressed in units of "weber" (kg⋅m2⋅s−2⋅A−1) or perhaps "tesla" ( kg⋅s−2⋅A−1)
The copper wire of course will be carrying a certain voltage, at some number of amps - dependent on (I think) the number of "turns" of the copper wire, and (I'm guessing) something to do with the speed of the magnet (the unit second-2), and it's strength (the unit kg) and maybe something to do with size (the unit meters2).
Can anyone explain that relationship in a practical (easy to understand in the real world) way?
Like - if I get an N52 neodymium magnet in a 1 cm cube, and I wrap 10 turns of copper around an iron core that's also a 1cm cube - and I move the magnet past the iron (so close it almost touches - so - 0 mm away) at a speed of 10 meters per second... what's my voltmeter and ammeter going to say?
This is not a "homework" question, nothing to do with scams, and I seriously spend ages trying to work this out before asking - please don't down vote my question: if you don't understand something ASK me.