I'm trying to understand how conductance that is measured in Siemens is equal to Amperes/Volt.

The SI units of Siemens is given to be in $$ kg^{-1}m^{-2}s^3A^2 $$ (link). I am not sure how this is related to A/V.

Could someone explain?


1 V is equivalent to 1 joule per coulomb (meaning, it takes 1 J of energy to move 1 C of charge across a potential difference of 1 V).

1 J is \$1\ \rm kg\ m^2\ s^{-2}\$.

1 C is \$1\ \rm A\cdot s\$.

So 1 V is \$ 1\rm\ kg\ m^2\ s^{-3}\ A^{-1}\$

  • \$\begingroup\$ The joys of dimensional analysis with Rayleigh and Buckingham... \$\endgroup\$ – Solar Mike Feb 18 '19 at 8:32

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