I have a this circuit:
I am asked to find |H(\$\omega\$)| in its simplest form.
I approached the problem by first recognizing that the first op am was a standard inverter. With that I basically rewrote the circuit so that the second op amp had a common input of
Using a voltage divider for C1 and R6 I found the transfer function to be:
\$(2R_x/(R_x+Z_c)) = -(V_o -Vi)/V_i \$
assuming that I did that right which is probably not a good assumption, the questions asks choose R6 and C1 so \$ \angle H(2\pi*10^3) = -90^\circ \$
I'm not sure how to get the transfer function from a magnitude to an angle so I can sub 1K (a practical value for an op amp) in for R6 and solve for C1?
Any help with this homework assignment is appreciated.