I have 2 problems with diode clampers that I don't understand
First, in this circuit for example:
In the positive half cycle, the voltage across the diode is the diode drop of 0.7 V
Then the voltage across the load resistance must be 0.7 V
Then isn't that a constant dc voltage? Why is it that when it gets clamped it appears as a sinusoidal peak? In which, the resulting shift happens like this:
My second question is specified to this following example:
Analyzing the positive half cycle, the diode is reverse biased, then the voltage across the load resistance should be zero ( Me assuming that the capacitor cannot fully charge instantaneously ) But this isn't the case, the input actually shifts by 14.3 V upwards.
To try to make sense of this, maybe they assume that the capacitor needs no time to charge, so it charges up to the peak of the input voltage V_p(in). But still there's a problem, that would produce a shift of 15 V upwards, not 14.3, then there must have been a voltage drop across the diode, but how did that voltage drop occur in the positive half cycle if it's reverse biased? Thanks.