2
\$\begingroup\$

enter image description here

I understand the whole circuit, except for the use of capacitor 3. What's its purpose in here?

\$\endgroup\$
2
\$\begingroup\$

C3 provides the reference signal from the primary of the transformer to be combined with the signal from the secondary of the transformer that resonates at the centre frequency of operation. The two diodes then rectify the combination.

At the centre frequency the primary and secondary signals are in phase and the net result is zero output. As the frequency deviates from the centre the phase of the secondary changes relative to the primary. As a result the voltage at the output of the diodes changes positive or negative depending upon the direction of the frequency change.

C1, C2, R1 and R2 are selected so that D1 and D2 rectify the RF signal to provide a voltage proportional to the amplitude of the summation of the signal through C3 and the voltage across the secondary. The time constant of C1R1 and C2R2 should be much longer than the RF period but short relative to the highest modulation frequency.

It looks like this diagram was taken from this website that describes the operation: Foster Seeley Discriminator

A more detailed description is here FM demodulation

\$\endgroup\$
  • \$\begingroup\$ I don't understand if C1R1 and C2R2 are acting as low pass filters, because supposedly by that stage you want to filter out high frequencies, but the layout of a low pass filter is the opposite, with the resistance being first and the capacitor second, so what is going on at that stage? Mostly, what does C1R1 and C2R2 time constant imply with respect to the frequencies filtered? \$\endgroup\$ – The AFOH Mar 1 at 0:55
  • \$\begingroup\$ If I've researched this properly, a capacitor should filter out a range of high frequencies just by taking them in because of its low reactance to them while letting the rest of the signal go to output, in this case, via resistance. Right? \$\endgroup\$ – The AFOH Mar 1 at 1:04
  • \$\begingroup\$ @TheAFOH - C1R1 together with D1 form a half-wave rectifier (C2R2 &D2 behave similarly). The time constant should be much longer than the period of the RF input signal (eg 10.7MHz) but shorter than the period of the audio (e.g. 15kHz). A capacitor by itself does not "filter out" anything. A capacitor's reactance does decrease as the frequency increases. In conjunction with other components filtering action may occur. \$\endgroup\$ – Kevin White Mar 1 at 2:49

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.