In the diagram below the npn transistor is in the cutoff region. The book says that both EB and CB junction are reverse biased. My question is about:
A) the EB junction. How is it reverse biased? Isn't it zero biased since both base and emitter are grounded?
B) also the book says that in cutoff region entire Vcc will be available at output. But what about the voltage drop at resistor connected to collector? Isn't output voltage supposed to be less than Vcc even in cutoff region?