in this clamper circuit it's easy for me to determine the output waveform:
This is how I do it:
In the positive half cycle, the diode is forward biased with a drop of 0.7 V, so the positive half output is limited to 0.7 V
In the negative half cycle, the diode is reverse biased, and the capacitor has a voltage of 3.3 V, so the negative half output, by applying Kirchhoff:
-Vout - Vin - Vc = 0 Vout = -Vin - Vc = -4-3.3 = -7.3 V
So the output waveform has a positive peak of 0.7 V and negative peak of -7.3 V
But when he asks me to turn the diode around, like this:
I face problems when I apply Kirchhoff, this is how I do it:
In the first positive half cycle, the diode is reverse biased and the capacitor has a voltage of 3.3 V, applying Kirchhoff:
-Vout + Vin - Vc = 0 Vout = Vin - Vc = 4-3.3 = 0.7 V
In the negative half cycle, the diode is forward biased, so it has a drop of 0.7 V, so the output is limited to -0.7 V
I end up with a positive peak of 0.7 V and a negative peak of - 0.7 V , but this should be wrong, the right answer should be the exact same as the first circuit but with different signs, I don't understand how though, can someone let me know, thank you.