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I have created a basic series and parallel rlc circuit in LTPSICE.
According to this http://lpsa.swarthmore.edu/Analogs/ElectricalMechanicalAnalogs.html and https://www.tutorialspoint.com/control_systems/control_systems_electrical_analogies_mechanical.htm we can see that the output must be same if the values are interchanged.

In the circuit I used an inductor of 1 H, a capacitor of 5 mF and a resistor of 260.8u\$\Omega\$ for the series RLC.
For the parallel RLC we have to interchange L and C values and R=1/R as shown in the links. So, R=1/0.0002608, C=1F and L=0.005H. But I am not able to get the same output.

Can somebody help me with it?

enter image description here

The current in series rlc : enter image description here

The voltage in parallel rlc: enter image description here

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  • \$\begingroup\$ What is "output"? Voltage? Current? Both? \$\endgroup\$ – Dmitry Grigoryev Mar 15 at 11:42
  • \$\begingroup\$ according to the links the voltage across capacior in series circuit should be equal to current across the inductor in parallel circuit \$\endgroup\$ – Bharath raj Mar 15 at 11:47
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    \$\begingroup\$ Hi Solar Mike, check out the link. I am trying to do a mechanical circuit analogous to electrical. There are 2 methods to do that. And according to the formulas it should be same in 2 methods as shown in tutorialspoint.com/control_systems/… . \$\endgroup\$ – Bharath raj Mar 15 at 11:53
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    \$\begingroup\$ The series RLC has a voltage source (=force input) and the output here is "current" (=velocity), the parallel RLC has a current source (=force input) with output "voltage" (=velocity). The shapes of both outputs should be equal as both represent velocity \$\endgroup\$ – Huisman Mar 15 at 12:15
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    \$\begingroup\$ You are exiting an RC tank which is damped out by R eventually (increase stop time to e.g. 10000 sec). But with the default series resistance in both the inductors, this goes even faster. \$\endgroup\$ – Huisman Mar 15 at 12:40

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