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ResistorsI have two resistors that I'm trying to figure the values of.

One is black blue silver gold black

Second is black orange silver gold black

Can anyone help with these values?

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  • \$\begingroup\$ What's "blk"? Black? \$\endgroup\$ – winny Mar 19 at 16:19
  • \$\begingroup\$ Try 6.8 ohms and 3.9 ohms (Black is possibly the base colour of the resistor and silver is possibly grey and you may be mistaking the other silver for white). \$\endgroup\$ – Andy aka Mar 19 at 16:19
  • \$\begingroup\$ I do apologize for having to edit the blk. I was able to upload an image of them just in case. \$\endgroup\$ – Pat Mar 19 at 19:34
  • \$\begingroup\$ @Pat - Hi, (a) Have you tried measuring them with a multimeter? If so, what did you measure? If not, what is preventing you measuring them? (b) What is the context to the question? There is no obvious sign of damage, so why are you trying to find their values? I just want to avoid the situation where you do find their values, but that turns out not to help with some other underlying problem, which hasn't been explained yet... Thanks. \$\endgroup\$ – SamGibson Mar 19 at 21:01
  • \$\begingroup\$ @SamGibson I have measured them and they measure .8-.9 ohms (the pink resistor) and the blue is .11 ohms. These are out of a computer power supply that stopped working. I replaced a bad capacitor and checked two diodes and these two resistors that were part of that circuit, the diodes tested fine but these two resistors seemed way off. \$\endgroup\$ – Pat Mar 21 at 0:07
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These are most likely 6.8Ω or 6.9Ω and 3.8Ω or 3.9Ω non-inductive type resistors. What you are calling silver is most likely either grey or white.

The final black band means non inductive type, and while gold is often a tolerance indicator, in this case it is the multiplier (0.1X).

See this chart: enter image description here

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  • \$\begingroup\$ Interesting suggestion, however: "non-inductive type resistors" - those components (if they really are resistors and not inductors) appear to show the shape expected of a wirewound element under the paint, don't they, which would be inductive. So I can't reconcile the shape of the resistors (looking just what I'd expect for being constructed as wirewound) with that decoding (claiming they are non-inductive). See what I mean? I'm open to being shown that they are definitely non-inductive, if there is some evidence, so I could be wrong - but I can almost see the wire in them... \$\endgroup\$ – SamGibson Mar 19 at 21:06
  • \$\begingroup\$ @SamGibson They are what is called bifilar-wound. They are coiled, but in both directions overlapping so the fields cancel. They do indeed look wire-wound, because they are! This is why the black band is needed, to alert you to the fact that although they LOOK like they would be inductive, they are not. \$\endgroup\$ – evildemonic Mar 19 at 21:27

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