0
\$\begingroup\$

"If no controlling current or voltage associated with the dependent source is of interest, we may simply find the Thévenin equivalent connected to the inductor and capacitor."

This is what's written in Engineering Circuit Analysis- Hyatt, Kimberly.

After doing a question this way, I found it a little strange: We're finding the Thevenin Equivalent which includes an independent voltage(Thevenin) source and a Thevenin Resistance, and the total circuit consists of the capacitor and inductor as well. Since it includes an independent voltage source the total response should be the sum of the natural and the forced response, but we're not including the forced response in it. Why so?

enter image description here

\$\endgroup\$
  • 1
    \$\begingroup\$ Reading your question it looks like you are referring to a specific schematic - can you include it? \$\endgroup\$ – Vladimir Cravero Mar 20 '19 at 12:55
  • \$\begingroup\$ The image you included talks about finding only the equivalent resistance, \$R_{eq}\$, not a Thevenin equivalent circuit or the Thevenin voltage source. \$\endgroup\$ – Elliot Alderson Mar 20 '19 at 15:52
  • \$\begingroup\$ Exactly, why we're concerned about only the Thevenin Resistance and not the Thevenin Voltage, it's as if we're ignoring it without any reason. I'm asking why are we doing so? \$\endgroup\$ – Adarsh Kumar Mar 21 '19 at 11:27
0
\$\begingroup\$

I believe what they are saying is the dependent source and the two resistors can be boiled down into an R-equivalent resistor (with the excitation source removed). This would be advantageous because one could then analyze the circuit as an RLC which simplifies the math.

So what they do is remove the L and the C and subsitute a current source, and then say "Hey, all these components are linear and function like a resistor"

If you go around the loop and find the equivalent to Vtest you get a resistor, this allows you to ignore

What they are trying to show is that for some circuits it is easier to simplify the circuit before trying to solve the circuit.

We are not concerned with the forced response of the circuit because there is no zero state response, the circuit has to be excited for there to be a response.

In addition 1A current through the loop helps you find Vtest for an initial condition, which will help you find Vc, because when the circuit starts up, the inductor is shorted.

| improve this answer | |
\$\endgroup\$
  • \$\begingroup\$ I understand that, what I'm asking is if I make the Thevenin Equivalent of the above circuit then it includes a Thevenin Independent source and a Thevenin Resistance, what you're suggesting(and perhaps the book suggests the same) is that you ignore the Thevenin Independent source, then even the Thevenin Circuit simplifies to only consisting of a Resistor, a Capacitor and an Inductor, and then simply find the natural response, but my doubt is how can we just neglect the Thevenin Independent Voltage source in the first place? \$\endgroup\$ – Adarsh Kumar Mar 21 '19 at 11:25

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.