# What is the direction of negative reactive power

In a R+1/(jwC) load (AC)voltage lags current with θ degrees. Reactive power Q is negative because sin(θ) is negative. My question is how can a capacitive load deliver power to the source wich is supposed to supply the power? Im sure I do not completely understand the subject, can someone explain my faults? Thank you for your help, Nick.

• Do you mean $j\omega L$ or $\frac{1}{j\omega C}$? – Andy aka Mar 21 at 12:52
• Yes I meant 1/(jwC) – N. Berg Mar 21 at 13:39