I have a basic understanding of electrical circuits, and successfully dimmed similar drivers using an external 10 VDC power source. But this time, I need to do so without an external source. Note this "A-Type" model has an unregulated auxiliary DC output (last page of spec sheet) that may be useful for this.
I tried connecting a 100K logarithmic potentiometer as a series resistor (only two terminals) between DIM+ and DIM-. That works fairly well for dimming, going down to minimal brightness. The problem is this does not achieve 100% brightness; 100K ohm causes dimming. I tested a variety of fixed resistors between DIM+ and DIM- in series, and found even 10 M ohm still causes dimming.
First Question: Am I correct to conclude that simply introducing resistance to the dimming circuit is not how it should be used? Rather that a voltage must be introduced between DIM+ and DIM-?
Second Question: Is it safe to use the auxiliary VDC output to drive the dimming circuit? Specifically I would connect the potentiometer as a voltage divider; potentiometer outer pins to AUX+ and AUX- (0.12 mA current in AUX circuit), potentiometer center pin to DIM+, AUX- to DIM-. I should also be able to swap the CW/CCW control by alternatively center pin to DIM-, and AUX+ to DIM+.
This seems correct to me, but I'm asking for confirmation and advice before I ruin an expensive driver. Thanks for the help :).