How can I Thevenize the following circuit looking into the out terminal:
I want to deduce this circuit to a source and a single series impedance.
Here what I tried:
\$\frac{R1\cdot R2}{R1+R2}\$ is in series with C1
This becomes \$\sqrt{\frac{R1\cdot R2}{R1+R2}^2 + \frac{1}{\omega C1}^2 }\$
And now \$\sqrt{\frac{R1\cdot R2}{R1+R2}^2 + \frac{1}{\omega C1}^2 }\$ is in parallel with R5
I cannot proceed more. How could this be achieved if mine is wrong as an alternative way?
is the following correct?: \$\frac{R1\cdot R2}{R1+R2}\$ is in series with C1
\$Z_{thevenin} = \frac {\sqrt{\frac{R1\cdot R2}{R1+R2}^2 + \frac{1}{\omega C1}^2 } \cdot R5} {\sqrt{\frac{R1\cdot R2}{R1+R2}^2 + \frac{1}{\omega C1}^2 } + R5}\$
And the Thevenin voltage needed to be found as well.
Vth = V1 * ((|R5+(1/jwc)| // R2)/ (R1 + (|R5+(1/jwc)| // R2))) * R5/|R5+(1/jwc)|