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For a university purpose I am preparing a project, actually I am thinking of using a photodiode in reverse bias in order to measure intensity of light.

I divided this project in some phases:

1) Current-voltage converter as current of diode is very small I convert it to voltage

2) Noise filter , in this case, how can I determine which frequencies I should eliminate and how? Consider that I am not very good at this, is it even possible to eliminate noise produced by photodiode itself?

3) Amplification of signal

Can anyone help me to understand how to do second step?

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  • \$\begingroup\$ What measurement bandwidth are you concerned with? \$\endgroup\$ – Andy aka Apr 4 at 10:11
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    \$\begingroup\$ Transimpedance amplifier could be a good starting point. \$\endgroup\$ – Marko Buršič Apr 4 at 10:38
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    \$\begingroup\$ Please write proper sentences with fully written words, and proper punctuation and capitalisation. If you practise doing so in your everyday things, you will do better when you write reports and papers for your university courses. \$\endgroup\$ – JRE Apr 4 at 11:04
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    \$\begingroup\$ The light intensity changes by time to time. The bandwidth in Hz determines how fast your system can response/measure to those changes and also give insight towards your filter cut-off frequency. \$\endgroup\$ – Unknown123 Apr 4 at 17:38
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    \$\begingroup\$ @amrit2 Are you measuring radiant intensity or luminous intensity? Are you aware that these both are based on a per-unit-solid-angle and that you need to take this into account when making measurements. If the light source is Lambertian, or something else, or if the source surface plane (if that is descriptive) is at an angle, you'll need to specify more things as well. If you seek accuracy relative to traceable standards, you need to say so, too. Etc. The more you discuss the details of the situation, the better your answers and the less we need to write. \$\endgroup\$ – jonk Apr 4 at 20:21

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