# Exercise question about Thévenin theorem

I'm new to Thevenin's theorem and I'm trying to figure out this simple one.

I did what's on the next figure. I'm wondering If I can join the cables as I did and I could say that the voltage across $$\R_{1}\$$ is also $$\V_{th}\$$ since they are in parallel. The answer says $$\R_{eq}=R_{1}\$$. But I'm getting $$\R_{eq}=R_{1}+R_2\$$.

• are you trying to compute A? – analogsystemsrf Apr 4 '19 at 16:27
• Yes A with respect to the ground node. – FelipeMedLev Apr 4 '19 at 17:00

R1 ia shorted with the conducting wire in place of V1 so the parallel equivalent resistance is 0 ohm (For two resistances in parallel, equivalent resistance is $R=\ frac{R1×R2}{R1+R2}$, If any resistance is zero, equivalent resisatnce is also zero). R3 has been open circuited correctly therefore the thevenin resistance is R2 and not R1
• I don't understand the part "$R_{1}$ is shorted with the wire in place of $V_1$". Doesn't it become a closed circuit? – FelipeMedLev Apr 4 '19 at 16:57