# Implementing logic expression and the truth table of logic function

(a) Expression for $$\Z\$$

$$\Z=(B+\overline{C})A+B(C+\overline{D})+BD\$$

$$\Z=AB+A\overline{C}+BC+B\overline{D}+BD\$$

$$\Z=AB+\overline{A}C+B\$$

$$\Z=B+A\overline{C}\$$

(b) Truth table

A B C || Z
==========
0 0 0 || 0
0 0 1 || 0
0 1 0 || 1
0 1 1 || 1
1 0 0 || 1
1 0 1 || 0
1 1 0 || 1
1 1 1 || 1


(c) Karnaugh Map

       | BC  00  01 11 10
------------------------
A  0  |     0  1  1  1

1  |     1  0  1  1


I was sure about what the last two questions (d) and (e) were asking me. Can anyone provide some guidance on how to solve these last two questions? Thank you in advance.