0
\$\begingroup\$

It is not completely clear to me, which pins need to be free (disconnected from other components) in order to flash the NodeMCU via USB with a firmware. Of course, this depends on the connected components. But let's assume reasonable worst case scenario. e.g. LED with a resistor, which pulls down GPIO0. I was wondering, if RXD0-TXD0 pins (GPIO3 and GPIO1) also need to be disconnected? e.g. I have ublox GPS Neo 6M module connected to (only) RX on NodeMCU and I can't upload when this is connected. I left TX not connected to get debug messages via USB.

Is it possible to flash via USB->UART1? Is the USB-UART chip capable of this? If not, then also GPIO3 and GPIO1 need to be "free". The reasons are:

  1. For beginners to understand, why and what to disconnect, when they have issues with uploading their sketch/firmware.
  2. When device is in an enclosure, it might be difficult to disconnect components.
  3. When device is soldered, it will be difficult to disconnect. In order to plan accordingly, one might introduce switches on certain pins to avoid such problems.

Basically, what pins may cause issues to upload firmware/sketch, when connected to certain components during the upload?

Module: Lolin v3, but it would be interesting to know for others too.

\$\endgroup\$
  • \$\begingroup\$ Pardon. What are you trying to do? It's unclear for me. Why would you want to flash it without disconnects everything first? Which module and version are you using? There are plenty of it. Such as AiThinker ESP-01 towards ESP-14, NodeMCU DevKit V1 towards V3 and many more. Take the photo of the module if you're confused. \$\endgroup\$ – Unknown123 Apr 6 at 7:01
  • \$\begingroup\$ No problem, question was clear in my mind but after reading again, I understand it wasn't very clear after all. I added more information. \$\endgroup\$ – Genom Apr 6 at 7:22

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.