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I am given a circuit below and I was hoping to clear up some misunderstanding I may have about conducting and non-conducting diodes. I am not sure which part of my knowledge is wrong, although I know that something is wrong as I have gotten the following question wrong. Below is my working out, alongside the question:

I have found that the diode connected to the 2V will be conducting, to which the output voltage will be 2-0.7 = 1.3V.

I have come to the conclusion that this diode will be conducting because it means that it will stop the other diode connected to the 8V from conducting as 2V < 8V.

Whereas if it had been the diode connected to the 8V that was conducting, then the diode connected to the 2V would also conduct, leading to two different output voltages...

I appreciate any help,

thank you.

enter image description here

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  • \$\begingroup\$ When a diode conducts, the anode is 0.7 V higher than the cathode. Reconsider the 1.3 V. \$\endgroup\$ – CL. Apr 7 at 7:17
  • \$\begingroup\$ Assuming that D2 conducts: from where to where does the current flow? What is the voltage drop over the resistor? \$\endgroup\$ – CL. Apr 7 at 7:18
  • \$\begingroup\$ So instead of 1.3, it would be 2.7? \$\endgroup\$ – Michel Apr 7 at 7:21
  • \$\begingroup\$ Please use mention feature to notify the person, else they won't notice if you're replying or not. \$\endgroup\$ – Unknown123 Apr 8 at 11:12
  • \$\begingroup\$ What is the anode voltage of D1? It should give you a clue to determine the cathode voltage as CL. already explained. \$\endgroup\$ – Unknown123 Apr 8 at 11:15

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