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To find the open circuit voltage between C and D, can I assume that no current flows through the current source between A and B. If it does not, the Thevenin voltage is 10V. But since it is not an ideal current source some current should flow through it. Also, to find the short circuit current V_x = 0 (short circuit between C and D). So should the current source be not considered while calculating the short circuit current. If so I will get the short circuit current as 1mA. But this analysis does not seem to be correct because it is independent of the current source.

Please help

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closed as off-topic by MCG, Elliot Alderson, Finbarr, RoyC, laptop2d Apr 16 at 15:56

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  • 6
    \$\begingroup\$ I'm voting to close this question as off-topic because this is a homework question without an attempt at a solution. This, and there are so, so many questions about finding Thevenin voltage and current on here. And a quick Google search will yield hundreds of results \$\endgroup\$ – MCG Apr 15 at 13:40
  • 2
    \$\begingroup\$ Why would you think you can assume no current in the open-circuit case? Why do you think that the current source is not ideal? You should explore your thinking for those two questions and then I think you will be able to answer your own question. \$\endgroup\$ – Elliot Alderson Apr 15 at 14:07
  • \$\begingroup\$ Every assumption you make is wrong. \$\endgroup\$ – Chu Apr 15 at 16:42

The only assumption that you can make here is: There is no current flow thru the 5k resistor between nodes A and C. So ignore it. So \$ V_{th}=V_{oc} = V_{CD} = V_{AB} = V_X\$ Then ask yourself two questions:

  • What is the current flowing through the circuit you are left with ?
  • Can you write a simple KVL equation for the only loop you are left behind with ?

You will reach the answer.


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