We have a 3x3 mm circular thin plate, which is made of copper, aluminium similar materials and thickness of the plate is 1 mm i.e. a very light and small piece of metal.

To lift this plate about 2 mm (against gravity), how much current is required? Is there a mathematical formula? To investigate whether there is a realistic approach for our situation, we need the help of experienced people.

To help image the setup, see below (except, we'll use solid not a ring):

drawing of setup

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    \$\begingroup\$ magnetic levitation requires an AC supply \$\endgroup\$ – Jasen Apr 18 '19 at 10:06
  • \$\begingroup\$ I revised the title and eliminated the reference too a battery to make the question more realistic and consistent with the illustration. Perhaps that will encourage someone else to answer. \$\endgroup\$ – Charles Cowie Apr 18 '19 at 15:02

The image shown is called a repulsion-ring demonstration. In the image, the iron rod passing through the ring helps to couple the magnetic field with the ring and prevent the ring from moving off to the side. Without the rod, repelling the conductive object will require a higher current and/or more turns in the coil. Also the direction of motion will be more difficult to control.

Alternating or pulsed current is required in the coil. The dimensions and specific material of the repelled object helps to determine the current induced and thus the force on the object.

The described technique is used in waste recycling to separate conductive material from non-magnetic waste materials. Magnetic waste is first separated by magnetic attraction.

Searching the internet for repulsion-coil information or information about magnetic separation of conductive materials may lead to specific information about designing such a system.

Others here may be able to offer more specific advice, but the question may be deemed too broad for this site.


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