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In the EVM datasheet schematic, two input beads and 2 output beads are used.

In my application, I drive 56V 5A COB LED. Input voltage is 22-50V, so input current can be ~6-13A. I read on Internet, that beads saturate and lose their filtering efficiency, so, it is better to use beads with current ratings 3-4 times higher. How can I implement such filter, as in the example in the datasheet? There are no ferrite beads with current ratings higher than 11A.

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You can use several beads in parallel. The current capability is multiplied, and inductance is fraction of one bead.

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  • \$\begingroup\$ To use with 13A I will need to be (as was suggested 3-4x) at 40A, so, I will need 4 10A beads in parallel for positive and for negative, a lot of parts. Is there a different way? \$\endgroup\$ – Roman Simonyan Apr 22 '19 at 14:22

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