0
\$\begingroup\$

I'm designing a small circuit using an op-amp for a temperature sensor (PT100). I took the design online (see below). enter image description here

I tried to find out the formula for finding the value Vout as a function of the input voltage. I've used the KCL (I think it's Kirshoff-current-law) at the various junction points. I got a formula that gives values that are offsetted by 0.2Volts from the output produce by a simulation of the circuit in Proteus (original diagram in LTSpice as seen in the picture above). My question is: is it common for proteus to add an offset during the simulation, or am I necessarily making an error in my computations. Thanks in advance

\$\endgroup\$
12
  • 3
    \$\begingroup\$ How about drawing a normal circuit with right angles at the very least? \$\endgroup\$
    – Eugene Sh.
    Commented Apr 30, 2019 at 19:14
  • 3
    \$\begingroup\$ Isn't this LTSpice, not Proteus? \$\endgroup\$ Commented Apr 30, 2019 at 19:16
  • 1
    \$\begingroup\$ Most definitely LTSpice \$\endgroup\$
    – Eugene Sh.
    Commented Apr 30, 2019 at 19:42
  • \$\begingroup\$ Do you know about net labels in LT spice? Hit the F4 key \$\endgroup\$
    – Voltage Spike
    Commented Apr 30, 2019 at 19:42
  • \$\begingroup\$ @Nwells clean up your question, it's confusing, there is no way to answer it \$\endgroup\$
    – Voltage Spike
    Commented Apr 30, 2019 at 19:43

1 Answer 1

1
\$\begingroup\$

I've found a pretty acceptable solution. The formula for the output voltage of the diagram above is provided in another question, I've recently posted: Output Voltage Formula verification of Operational Amplifier circuit. The diagram can easily be simulated in Proteus and provide a temperature range between 0 and 400 degree celcius. enter image description here Where Rx=R6=Resistance of the PT100 sensor.

The problem I was having was that I was wrongly connecting my PT100 (3-wires) RTD within the circuit (the above circuit assumes a 2-wire RTD). The other mistake was to use a 5V supply source for the Op-Amp: no, the voltage source for the op-amp needs to be at least 6V. Preferably, the op-amp should be powered by a 6V and -6V as I still get wrong results with temperatures below 50 degree Celsius. In my case, I'm mostly concerned with temperatures above 100 degree Celcius. So I'm fine with only a 6V supply for the Op-Amp.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.