My question is two-fold:
Where does the input impedance come from?
I'm wondering where the input impedance of your average multimeter or oscilloscope comes from? Is it just the input impedance to the device's input stage (such as an amplifier or ADC input stage), or is it the impedance of an actual resistor? If it is the impedance of an actual resistor, then why is there a resistor at all? Why not just the input circuitry?
I measured the input impedance of my oscilloscope with a DMM. When the scope was turned off, the DMM measured about \$1.2\mathrm{M\Omega}\$. However, when the scope was turned on, the DMM measured pretty much exactly \$1\mathrm{M\Omega}\$ (I could even see the 1V test input applied by the DMM on the oscilloscope screen!). This suggests to me that there is active circuitry involved in the scope's input impedance. If this is true, how can the input impedance be so precisely controlled? Based on my understanding, the input impedance to active circuitry will depend somewhat on the exact transistor characteristics.
Why can't the input impedance be much higher?
Why is the input impedance of an oscilloscope a standard \$1\mathrm{M\Omega}\$? Why can't it be higher than that? FET input stages can achieve input impedances on the order of teraohms! Why have such a low input impedance?
I suppose one benefit of a precise standard \$1\mathrm{M\Omega}\$ is it allows 10X probes and the like, which would only work if the scope had a precise input impedance that wasn't unreasonably large (like that of a FET input stage). However, even if the scope had a really high input impedance (e.g., teraohms), it seems to me that you could still have 10X probes just by having a 10:1 voltage divider inside the probe itself, with the scope measuring across a \$1\mathrm{M\Omega}\$ resistor inside the probe. If it had an input impedance on the order of teraohms, this would seem to be feasible.
Am I misunderstanding the input circuitry of a scope? Is it more complicated than I'm making it out to be? What are your thoughts on this?
The reason I thought of this is that I've recently been trying to measure the common-mode input impedance of an emitter-coupled differential pair, which is much larger than the scope input impedance, so it made me wonder why the input impedance can't be larger.